. Calculate the weight of given real gas having compressibility factor 0.65 and occupies 0.4 L at 40 atm and 27∘C.(mol. wt. of gas =44gmol−)

wt.= w g;Z = 0.65; V = 0.4 L;P=40atm.;T=27+273=300Kmol. wt. =44gmol−;n= wt.  mol.wt. = wg 44 gmol −= w 44 mole We know that :          Z=PVnRT=PV×44mol−wRT∴ w=PV×44ZRT        =40atm×0.4L×44gmol−0.65×0.0821LatmK−mol−×300K        =43.97g