Q.

Calculate the work involved when 1 mole of an ideal gas is compressed reversibly from 1.00 bar to 5.00 bar at a constant temperature of 300 K.

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a

-14.01 KJ

b

+18.02 KJ

c

4.01 KJ

d

-8.02 KJ

answer is C.

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Detailed Solution

w=-2.303 nRT log P1P2 So, w = -2.303 × 1 × 8.314 × 300 log 15 =-2.303 × 8.314× 300 log 1 - log 5 = -5744.14 × 0-0.6990 =4015.15 J =4.01 KJ
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Calculate the work involved when 1 mole of an ideal gas is compressed reversibly from 1.00 bar to 5.00 bar at a constant temperature of 300 K.