In the Cannizzaro reaction given below,2PhCHO →-OH PhCH2OH+PhCO2−, the slowest step is

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the attack of -OH at the carbonyl group,

the transfer of hydride to the carbonyl group,

the abstraction of proton from the carboxylic acid,

the deprotonation of PhCH2OH.

answer is B.

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Detailed Solution

The possible mechanism isThe slowest step is the transfer of hydride to the carbonyl group as shown in step (ii).

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