A carbon compound containing carbon and oxygen has approximate molar mass equal to 290. On analysis it is found to contain 50% by mass of each element. Therefore, molecular formula of the compound is:
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a
C12O9
b
C4O3
c
C3O4
d
C9O12
answer is A.
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Detailed Solution
Element: C O % by mass: 50 50 Ratio by no. of atoms: 5012 5016Simplest ratio by no of atoms : 4 : 3.'. Empirical formula = C4O3And let molecular formula be (C4O3), ∴ 96n=290 or n=29096≃3.'. Molecular formula is C12O9