Carbon exhibits allotropy. About Fullerene C60, correct statement is
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a
It is the impure form of carbon
b
It is aromatic in nature
c
Each carbon atom in it forms four sigma bonds
d
It is thermodynamically most stable allotrope of carbon
answer is B.
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Detailed Solution
Each carbon atom forms three sigma bonds.The remaining electron of each carbon is delocalised in molecular orbitals;Aromatic in nature;Pure form of carbon;Graphite is thermodynamically most stable form of carbon; .