A Carnot engine works between 120°C and 30°C Calculate the efficiency. If the power produced by the engine is 400 watts, calculate the heat absorbed from the source and rejected to the sink every second.

Efficiency, η=T1−T2T1 Here T1 = 273 + 120 = 393 KT2=273+30=303K∴ η=393−303393=0.229=22.9% Again η=Q1−Q2Q1=WQ1Thus, heat absorbed from the source,Q1=Wη=4000.229=1747 watts  Also Q2Q1=T2T1.'. The heat rejected to the sink Q2=Q1×T2T1=1747×303393=1347 watts