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Q.

In the case of a first order reaction, the time required for 93.7 5% of reaction to take place is x times that required for half of the reaction. Find the value of x.

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answer is 4.

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Detailed Solution

t1/2=0.0693k1 Also, t93.75=2.303k1log⁡100100−93.75 =2.303k1log⁡1006.25=2.303k1log⁡24=4×2.303×log⁡2k1=4×0.693k1=4t1/2
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