First slide

PH of strong acids and strong bases

Question

20cc of ‘x’ M HCl is exactly neutralised by 40cc of 0.05M NaOH. The pH of HCl solution is

Easy

A

1.0
B

2.0
C

1.5
D

2.5

Solution

Equivalents of HCl = Equivalents of NaOH
⇒ 20 x10^-3 x = 40 x 10^-13 x0.05
⇒ x = 0.1
$[H^{+}] = 10^{- 1} ∴ P^{H} = 1$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App