The Cell $$Ag(s)Ag2SO4(s)Hg2SO4(aqstt)HgsSO4(s)Hg(i)$$∣$$Pt(s)$$ has emf of $$0.140V$$ at $$298K$$ and $$1$$ bar. Close to $$298$$ K emf varies with temperature by $$1.39$$ × $$10-4$$ $$VK-1$$. How much heat is absorbed by the cell if it discharges isothermally and reversibly to deposit one gram equivalent of copper from its aqueous solution in units of KJ? (1$$ F $$=$$ $$96479$$ $$C)

Question

The Cell  $$Ag(s)Ag2SO4(s)Hg2SO4(aqstt)HgsSO4(s)Hg(i)$$∣$$Pt(s)$$ has emf of $$0.140V$$ at $$298K$$ and $$1$$ bar. Close to $$298$$ K emf varies with temperature by $$1.39$$ × $$10-4$$ $$VK-1$$. How much heat is absorbed by the cell if it discharges isothermally and reversibly to deposit one gram equivalent of copper from its aqueous solution in units of KJ? (1$$ F $$=$$ $$96479$$ $$C)

Infinity Learn · Accepted Answer

$$12Hg2SO4s+Ags$$⇌$$Hgl+12AgSO4s$$ΔSΘ$$=F$$∂EΘ∂Tq $$=TDS$$ $$=$$ $$298$$ × $$13.41=4$$ KJ

Electrolytic cells

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$\frac{1}{2} H g_{2} S O_{4} (s) + A g_{s} ⇌ H g (l) + \frac{1}{2} A g S O_{4} (s)$
$Δ S^{Θ} = F \frac{\partial E^{Θ}}{\partial T}$
q =TDS = 298 × 13.41=4 KJ

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Electrolytic cells

Unlock the full solution & master the concept.

12Hg2SO4s+Ags⇌Hgl+12AgSO4sΔSΘ=F∂EΘ∂Tq =TDS = 298 × 13.41=4 KJ

Ready to Test Your Skills?

free study material

$\frac{1}{2} H g_{2} S O_{4} (s) + A g_{s} ⇌ H g (l) + \frac{1}{2} A g S O_{4} (s)$
$Δ S^{Θ} = F \frac{\partial E^{Θ}}{\partial T}$
q =TDS = 298 × 13.41=4 KJ