Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

The Cell  Ag(s)Ag2SO4(s)Hg2SO4(aqstt)HgsSO4(s)Hg(i)∣Pt(s) has emf of 0.140V at 298K and 1 bar. Close to 298 K emf varies with temperature by 1.39 × 10-4 VK-1. How much heat is absorbed by the cell if it discharges isothermally and reversibly to deposit one gram equivalent of copper from its aqueous solution in units of KJ? (1 F = 96479 C)

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya

answer is 4.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

12Hg2SO4s+Ags⇌Hgl+12AgSO4sΔSΘ=F∂EΘ∂Tq =TDS = 298 × 13.41=4 KJ
Watch 3-min video & get full concept clarity

courses

No courses found

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon