For the cell, CuCu2+∥Ag+Ag,Ecell ∘=+0.46V If concentration of Cu2+ ions is doubled, then Ecello will be

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halved

doubled

four times

remains the same

answer is D.

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Detailed Solution

Ecell ∘=Ecathode ∘−Eanode ∘i.e. it does not depend upon the concentration of ions , so remain the same.

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