For a cell involving one electron, E°cell =0.59 V at 298 K, the equilibrium constant for the cell reaction is [Given that 2.303RT¯=0.059 V atT=298 K ]

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answer is 4.

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Detailed Solution

According to Nernst equation, Ecell=Ecell−0.059nlog⁡Qc At equilibrium Ecell=0, ∴ Qc=KcEcell=0.059nlog⁡Kc⇒0.59=0.0591log⁡KcKc=antilog 10⇒Kc=1×1010

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