Q.
For a cell involving one electron, E°cell =0.59 V at 298 K, the equilibrium constant for the cell reaction is [Given that 2.303RT¯=0.059 V atT=298 K ]
see full answer
Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!
Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya
answer is 4.
(Unlock A.I Detailed Solution for FREE)
Ready to Test Your Skills?
Check your Performance Today with our Free Mock Test used by Toppers!
Take Free Test
Detailed Solution
According to Nernst equation, Ecell=Ecell−0.059nlogQc At equilibrium Ecell=0, ∴ Qc=KcEcell=0.059nlogKc⇒0.59=0.0591logKcKc=antilog 10⇒Kc=1×1010
Watch 3-min video & get full concept clarity