Cell notation of Daniel cell is Zns/Zn2+1M//Cu2+1M/Cus. Standard free energy change for the reaction occurring in Daniel cell is EZn2+/Zn0=-0.76 V, ECu2+/Cu0=+0.34 V

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-234.9 kJ

-212.3 kJ

-251.1 kJ

-205.2 kJ

answer is B.

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Detailed Solution

Ecell0=Ecathode0-Eanode0; Ecell0=+0.34V--0.76V=1.1 V ; Zns+Cu2+1M→Zn2+1M+Cus ; ∆0G=-nFEcell0; ∆0G=-2965001.1 J ; ∆0G=-296.51.1 kJ ; ∆0G=-212.3 kJ ;

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