First slide

Nernst Equation

Question

Cell notation of a galvanic cell is $Fe (s) |{Fe}^{+ 2} (C_{1})| |{Ag}^{+} (C_{2})| Ag (s)$ . Emf of the cell is maximum when $C_{1} : C_{2}^{2}$ is

Moderate

A

1
B

10
C

0.1
D

0.01

Solution

Cell reaction
$Fe (s) + 2 {Ag}^{+} (C_{2}) \to {Fe}^{+ 2} (C_{1}) + Ag (s)$
Nernst Equation
$\begin{array}{l} E_{cell} = E_{cell}^{o} - \frac{0 .0591}{2} \log \frac{[{Fe}^{+ 2}]}{{[{Ag}^{+}]}^{2}} \\ E_{cell} = E_{cell}^{o} - \frac{0 .0591}{2} \log \frac{C_{1}}{C_{2}^{2}} \\ E_{cell} \propto - \log \frac{C_{1}}{C_{2}^{2}} \end{array}$
Lesser the magnitude of $\frac{C_{1}}{C_{2}^{2}}$ higher will be the emf of the cell.

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