Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

Cell notation of a galvanic cell is represented as Ni(s)/Ni+2(M1)//Cl-(M2)//12Cl2(1atm), Pt(s). Emf of the cell is maximum when the values of M1 and M2 are

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

a

M1=M2=0.01 M

b

M1=1 M ; M2=1 M ;

c

M1= 0.1 M ; M2= 0.01 M ;

d

M1= 0.01 M ; M2= 0.1 M ;

answer is A.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

Anode (LHE) Ni(s)→ Ni+2(M1)+2e;Cathode (RHE) Cl2(1atm)+2e→ 2Cl-(M2)Net cell reaction : Ni(s)+Cl2(1atm)→ Ni+2(M1)+2Cl-(M2)Ecell=Ecell0-0.05912logNi+2Cl-2 ∴Ecell∝-logNi+2Cl-2Thus lesser the product of Ni+2Cl-2 higher will be the Ecell;The product of  Ni+2Cl-2 in each case is(1) option ….10-6(2) option ….1(3) option ….10-5(4) option ….10-4Minmum emf of the cell is when Ni+2=0.01 M and Cl- =0.01 M
Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon
personalised 1:1 online tutoring