For the cell prepared from electrode A and B; Electrode A:$$Cr2O72$$−∣$$Cr3+$$,Ered∘$$=+1.33V$$ and Electrode B:$$Fe3+$$∣$$Fe2+$$, Ered∘$$=0.77VWhich$$ of the following statements $$is/are$$ correct ?

Correct option is 4All of these

Questions

For the cell prepared from electrode A and B;
$Electrode A : {Cr}_{2} O_{7}^{2 -} ∣ {Cr}^{3 +}, E_{red}^{\circ} = + 1.33 V and$
$Electrode B : {Fe}^{3 +} ∣ {Fe}^{2 +}, E_{red}^{\circ} = 0 .77 V$
Which of the following statements is/are correct ?

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The electrons will flow from B to A when connection are made

The EMF of the cell will be 0.56V

A will be positive electrode

All of these

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detailed solution

Correct option is D

ERPCr2O72−/Cr3+∘2+= 1.33V and ERPFe3+/Fe2+∘2+=0.77V∴EopFe+2|Fe is more thus it will oxidise or electron willflow from Fe electrode to Cr electrode. Also Fe electrode will be negative. Also,Ecell o=EOPFe0+ERPCr0=−0.77+1.33

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