For the cell prepared from electrode A and B; Electrode A:Cr2O72−∣Cr3+,Ered∘=+1.33V and Electrode B:Fe3+∣Fe2+, Ered∘=0.77VWhich of the following statements is/are correct ?

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The electrons will flow from B to A when connection are made

The EMF of the cell will be 0.56V

A will be positive electrode

All of these

answer is D.

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Detailed Solution

ERPCr2O72−/Cr3+∘2+= 1.33V and ERPFe3+/Fe2+∘2+=0.77V∴EopFe+2|Fe is more thus it will oxidise or electron willflow from Fe electrode to Cr electrode. Also Fe electrode will be negative. Also,Ecell o=EOPFe0+ERPCr0=−0.77+1.33

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