For the cell prepared from electrode A and B; Electrode A:Cr2O72−∣Cr3+,Ered∘=+1.33V and Electrode B:Fe3+∣Fe2+, Ered∘=0.77VWhich of the following statements is/are correct ?
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
The electrons will flow from B to A when connection are made
b
The EMF of the cell will be 0.56V
c
A will be positive electrode
d
All of these
answer is D.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
ERPCr2O72−/Cr3+∘2+= 1.33V and ERPFe3+/Fe2+∘2+=0.77V∴EopFe+2|Fe is more thus it will oxidise or electron willflow from Fe electrode to Cr electrode. Also Fe electrode will be negative. Also,Ecell o=EOPFe0+ERPCr0=−0.77+1.33
For the cell prepared from electrode A and B; Electrode A:Cr2O72−∣Cr3+,Ered∘=+1.33V and Electrode B:Fe3+∣Fe2+, Ered∘=0.77VWhich of the following statements is/are correct ?