For the cell reaction:2Fe(aq)3++2I(aq)-⟶2Fe(aq)2++I2(aq)Eocell =0.24 V at 298 K. The standard Gibbs energy ΔrG°of the cell reaction is [Given that Faraday constant F=96500Cmol-1

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answer is 2.

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Detailed Solution

The standard Gibbs' energy ΔG°=-nFE°cell Value of n=2 ∴ ΔG°=-2×96500×0.24=-46320 J=-46.32 kJ/mol

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