First slide

Nernst Equation

Question

For the cell Zn/Zn²⁺//Cu²⁺/Cu, if the concentration of Zn²⁺ and Cu²⁺ ions is doubled, the emf of the cell

Easy

A

doubles
B

reduces to half
C

remains same
D

remains zero

Solution

From Nernst equation
${E_{cell}} = E_{cell}^o - \frac{{0.0591}}{2}\log \frac{{\left[ {Z{n^{ + 2}}} \right]}}{{\left[ {C{u^{ + 2}}} \right]}}$
When concentrations are doubled ratio $\frac{[Zn^{+2}]}{[Cu^{+2}]}$ remains same. E_cell remains same.

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