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Q.

For the cell Zn/Zn2+//Cu2+/Cu, if the concentration of Zn2+ and Cu2+ ions is doubled, the emf of the cell

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a

doubles

b

reduces to half

c

remains same

d

remains zero

answer is C.

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Detailed Solution

From Nernst equationWhen concentrations are doubled ratio remains same. Ecell remains same.
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For the cell Zn/Zn2+//Cu2+/Cu, if the concentration of Zn2+ and Cu2+ ions is doubled, the emf of the cell