First slide
Fundamentals of thermodynamics
Question

A certain engine which operates in a Carnot cycle absorbs .3.347 kJ at 400°C, how much work is done by the engine per cycle? The temperature of sink is 100°C.

Difficult
Solution

η=T2T1T2=1T1T2=1373673=0.446η=Δwq1 or  ΔW=η×q1=0.446×3.347=1.49kJ

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