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A certain engine which operates in a Carnot cycle absorbs .3.347 kJ at 400°C, how much work is done by the engine per cycle? The temperature of sink is 100°C.
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Correct option is A
η=T2−T1T2=1−T1T2=1−373673=0.446η=Δwq1 or ΔW=η×q1=0.446×3.347=1.49kJTalk to our academic expert!
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