A certain engine which operates in a Carnot cycle absorbs 3.347 kJ at 400°C, how much work is done by the engine per cycle? The temperature of sink is 100°C.

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1.49 kJ

2.51 kJ

1.85 kJ

2.98 kJ

answer is A.

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Detailed Solution

η=T2−T1T2=1−T1T2=1−373673=0.446η=Δwq1 or ΔW=η×q1=0.446×3.347=1.49kJ

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