In a certain operation 358 g of TiCl4 is reacted with 96 g of Mg. Calculate % yield of Ti if 32 g of Ti is actually obtained [At. wt. Ti = 48, Mg = 24] Hint:  358190  =  1.88

TiCl4       +         2Mg   →       Ti       +    2MgCl2             1mole   2moles  1mole(48g) given;   358190      9624          ?            =1.88      =4 moles   So TiCl4 is limiting reagent      1mole of TiCl4→ 48g of Ti 1.88moles of TiCl4→     ?a   mass of ‘Ti ’obtained  = 1.88×48gBut actual mass of ‘Ti’ obtained = 32g% yield of ‘Ti’ = 3248×1.88×100=35.4%