Q.

For a certain reaction, ΔH0 and ΔS0 respectively are 400 KJ & 200 J/mol/K. The process is non-spontaneous at

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answer is 3.

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Detailed Solution

∆G0=∆H0-T∆S0; ∆G0=+ve-T+ve; ∆G0 will be positive only when T
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