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Q.

At certain temperate Kw for water 4 × 10-14 which of the following is incorrect for pure water at the given temperature ?log 2 = 0.3

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a

pH = 6.4 and water is acidic

b

pH = 6.4 and water is neutral

c

pOH = 6.4 and water is neutral

d

pH + pOH = 13.4

answer is A.

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Detailed Solution

H+OH- = Kw = 4 × 10-14 In pure water  H+=OH- ∴   H+= 4 × 10-7 or PH = 7 - log 4 = 7-0.6=6.4pure water is neutral.POH=6.4
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