At certain temperature compound.AB2 (g) dissociates according to the reaction 2AB2(g)⇌2AB(g)+B2(g) With degree of dissociation α, which is small compared with unity. The expression of K p in terms of α and initial pressure P is :

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Pα32

Pα23

Pα33

Pα22

answer is A.

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Detailed Solution

2AB2(g)⇌2AB(g) + B2(g) t=0; p 0 0 teq. ; P-Pα Pα Pα2 kp=PAB2PB21PAB22=(pα)2(pα/2)(p-pα)2=pα32

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