Q.

At a certain temperature, the degree of dissociation of PCl5 was found to be 0.25 under a total pressure of 15 atm. The value of Kp for the dissociation of PCl5 in the reaction, PCl5g⇌PCl3g+Cl2g

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Detailed Solution

Initial moles of PCl5 = 1Degree of decomposition of PCl5 = 0.25Equilibrium presssure 15 atmMoles of PCl5 at equilibrium = (1 - 0.25) = 0.751 mole of PCl5 gives 1 mole of PCl3 and 1 mole of Cl20.25 moles of PCl5 gives _______ and _______. Total moles at equilibrium = 1 - 0.25 + 0.25 +0.25 = 1.25

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