Q.

At certain temperature,  pH of 0.001 N solution of NaOH  is 9. Ionic product of water at that temperature will be

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answer is 4.

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Detailed Solution

Temperature influences Kw; 0.001N NaOH, OH-=10-3; pOH=3; Given pH=9; pKw=9+3=12; Kw=10-12
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