First slide

Graham's law

Question

At certain temperature and pressure 4 grams of helium effuses out in 10 minutes. Under similar conditions ‘X’ grams of methane effuses out in 600 seconds. ‘X’ is equal to

Moderate

A

1 g
B

8 g
C

2 g
D

16 g

Solution

$\frac{W_{He}}{W_{{CH}_{4}}} = \sqrt{\frac{M_{He}}{M_{{CH}_{4}}}}; \frac{4}{W_{{CH}_{4}}} = \sqrt{\frac{4}{16}}; W_{{CH}_{4}} = 8 g$

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