At certain temperature for the reaction NH4HS(S)⇌NH3(g)+H2S(g) the equilibrium pressure found to be “P atm” . Now H2S(g) was added to it at same temperature until the partial pressure of H2S(g) at new equilibrium become “P atm”. The partial pressure of NH3 at new equilibrium is
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a
P4atm
b
2P atm
c
P2atm
d
P22atm
answer is A.
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Detailed Solution
For the given reaction =PNH3PH2S=P2atmP2atm=P24atm2As temperature remains the same, there is no change in equilibrium constant∴P24atm2=PNH3(Patm)Partial pressure of ammonia PNH3=P4 atm