At a certain temperature and a total pressure of 105 Pa, iodine vapours contain 40% by volume of iodine atoms at equilibrium [I2(g)⇌2I(g)] . Kp for the equilibrium will be

I2(g)⇌2I(g)                       ∵XI2+XI=1 XI=40%=0.4                             ⇒XI2=0.6 60%=0.6 Kp=(0.4×105)20.6×105         =0.4×105×0.4×1050.6×105         =0.83×105            =2.66×104