At a certain temperature and a total pressure of 105 Pa, iodine vapours contain 40% by volume of iodine atoms at equilibrium I2(g)⇌2I(g) KP for the equilibrium will be

I2(g)⇌2I(g)At equilibriumVolume percent of I(g) = 40%Volume percent of I2 (g) = 60%Volume percent = mole percentPartial pressure = Mole fraction Total presurePI2(g)=60100×105=6×104 PaPI(g)=40100×105=4×104 PaKP=PI(g)2PI2(g)KP=4×10426×104KP=2.67×104 Pa