First slide

Crystal field theory

Question

CFSE of [Mn(H₂O)₆]Cl₂ is

Easy

A

1.2 $∆_{0}$
B

-1.2 $∆_{0}$
C

Zero
D

+1.6 $∆_{0}$

Solution

H₂O is weak field ligand
Electronic configuration is $t_{2 g}^{3} e_{g}^{2}$
CFSE = [3(-0.4) + 2(0.6)] $∆_{0}$ = Zero

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