Q.

CH3Br→etherMgA→ CdCl2B→ CH3CH2CH2COCl; the compound ‘C’ in the reaction is

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a

b

c

d

answer is B.

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Detailed Solution

A  is  CH3MgBr; 2CH3MgBr+CdCl2→ CH32Cd(B)+2MgBrCl 2CH3CH2CH2COCl+CH32Cd→ CH3CH2CH2COCH3(C)+CdCl2
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CH3Br→etherMgA→ CdCl2B→ CH3CH2CH2COCl; the compound ‘C’ in the reaction is