CH3−CH=CH2→H2O/H+A; CH3-CH2-CHCH3-CHO→NaBH4B; Wrong statement is
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a
‘A’ can be obtained by hydroboration-oxidation of propene
b
Propene→750-800CConc.H2SO4X→H2OA;
c
‘B’ is 2-methyl-butan-1-ol
d
‘A’ and ‘B’ are Homologues
answer is A.
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Detailed Solution
I : Markovnikov’s addition of water;∴ A is CH3−CHOH−CH3;II. …….reduction;∴B is CH3-CH2-CCH3|H-CH2OHA and B are homologues;CH3−CH=CH2→b)H2O2/OH−a)B2H6/THFCH3−CH2−CH2OH option (1) is false