Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

CH3CH2COONa→NaOH+CaO/∆ P; CH3COONaaq→electrolysis Q;  The compounds P and Q are

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya

a

Homologues

b

Unsaturated hydrocarbons

c

Same compounds

d

Positional isomers

answer is C.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

CH3CH2COONa+NaOH →CaO/∆ CH3-CH3P+Na2CO3; 2CH3COONa+2H2O →electrolysis CH3 -CH3Q+2CO2+2NaOH+H2
Watch 3-min video & get full concept clarity

courses

No courses found

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon
CH3CH2COONa→NaOH+CaO/∆ P; CH3COONaaq→electrolysis Q;  The compounds P and Q are