CH3-CHBr-CH2Br→∆excess NaNH2A→excessC2H5BrB. Positional isomer of compound B is

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

CH3-CH2-C≡C-CH3

CH3-CH2-CH2-C≡CH

CH3-C≡C-CH2-CH2-CH3

CH3-CH2-C≡C-CH2-CH3

answer is B.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

CH3-CHBr-CH2Br→1st moleNaNH2CHBr=CH-CH3→2nd moleNaNH2CH3-C≡CH→excessNaNH2CH3-C≡C- Na+→ C2H5BrCH3-C≡C-C2H5(B)Positional isomer of (B) is 1-pentyne.

Watch 3-min video & get full concept clarity