CH3CHO+CH3CH2CHO→∆dil. NaOHProducts. The product in this reaction cannot be

This is a crossed aldol condensation between two aldehydes both contaning α-hydrogen atoms. The final product obtained after heating with dilute alkali will be α, ß-unsaturated carbonyl compound(1) CH3-CH=O+H2CH-CHO→CH3-CH=CH-CHO (2) CH3-CH2-CH=O+H2CCH3 -CHO→CH3-CH2-CH=CCH3 -CHO (3) CH3-CH=O+H2CCH3-CHO→CH3-CH=CCH3-CHO (4) CH3-CH2-CH=O+H2CH-CHO→CH3-CH2-CH=CH-CHO(1), (2) . . . self aldol products(3), (4) . . . crossed aldol products3-hexenal (4th option ) can never be the product