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Questions  

CH3CONH2  H2OLiAlH4 P;     CH3CONH2Br2+KOHQ;           P and Q are

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By Expert Faculty of Sri Chaitanya
a
Same compounds
b
Homologues
c
Functional isomers
d
Positional isomers
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detailed solution

Correct option is B

CH3−CONH2 →H2OLiAlH4 CH3CH2NH2(P)CH3−CONH2+Br2+4KOH  → CH3NH2Q+K2CO3+2KBr+2H2O P and Q are homologues


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