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CH3COOAg→Br2/CCl4A→Mg/etherB→D2OC. The compound ‘C’ is

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a

CH3 - D

b

CD4

c

CH3 - OD

d

CH(OD)3

answer is A.

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Detailed Solution

CH3−COOAg+Br2→CCl4CH3Br+CO2+AgBr . . . Hundsdicker's reaction.CH3−Br+Mg→dry etherCH3MgBrCH3MgBr+D−OD→CH3−D+MgODBr

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