CH3−COOH →1 moleBr2 / Red P A →C2H5OHKCN B →H3O+C. The compound ‘C’ in this conversion is

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Maleic acid

Succinic acid

Oxalic acid

Malonic acid

answer is D.

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Detailed Solution

A=CH2|Br −COOH ; B=CH2|CN −COOH ; C=CH2 | COOH −COOH

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