CH3−COOH→1 moleCl2/PA→C2H5OHNH3B; ‘B’ is the only optically inactive amino acid. ‘B’ forms a biodegradable polymer with

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CH3−CH2−CHOH−CH2−COOH

CH3−CHOH−CH2−COOH

H2N−CH2−CH2−CH2−CH2−CH2−COOH

HOOC−CH2OH

answer is C.

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Detailed Solution

A is Cl−CH2−COOH;B is H2N−CH2−COOH;B is glycine. Glycine forms biodegradable polymer with 6-amino caproic acid. The polymer is Nylon-2-nylon-6

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