${\mathrm{CH}}_4\left(\mathrm{g}\right)+2{\mathrm{O}}_2\left(\mathrm{g}\right)⟶{\mathrm{CO}}_2\left(\mathrm{g}\right)+2{\mathrm{H}}_2\mathrm{O}\left(\mathrm{g}\right)$

According to the above chemical reaction, following information have been given.

(i) One mole of ${\mathrm{CH}}_4$ (g ) reacts with two moles of ${\mathrm{O}}_2$(g) to give one mole of ${\mathrm{CO}}_2\left(\mathrm{g}\right)$ and two moles of ${\mathrm{H}}_2\mathrm{O}$ (g)

(ii) One molecule of ${\mathrm{CH}}_4$ (g) reacts with 2 molecules of ${\mathrm{O}}_2\left(\mathrm{g}\right)$ to give one molecule of ${\mathrm{CO}}_2\left(\mathrm{g}\right)$ and 2 molecules of ${\mathrm{H}}_2\mathrm{O}\left(\mathrm{g}\right)$

(iii) 22.4 L of ${\mathrm{CH}}_4$(g ) reacts with 45.4 L of ${\mathrm{O}}_2$ to give 22.7 L of ${\mathrm{CO}}_2\left(\mathrm{g}\right)$ and 45.4 L of ${\mathrm{H}}_2\mathrm{O}\left(\mathrm{g}\right)$

(iv) 16 g of ${\mathrm{CH}}_4$(g ) reacts with 2x 32 g of  ${\mathrm{O}}_2$ (g ) to give 44 g of ${\mathrm{CO}}_2\left(\mathrm{g}\right)$ and 2x 18 g of ${\mathrm{H}}_2\mathrm{O}\left(\mathrm{g}\right)$

From these information the true interconversion should be

• A

  rnass $\to$ moles $\to$ number of molecules

• B

  mass $\stackrel{ }{\rightleftharpoons }$ moles $\stackrel{ }{\rightleftharpoons }$ number of molecules

• C

  rnass $\to$ moles $\stackrel{ }{\rightleftharpoons }$ nurnber of molecules

• D

  mass = moles = number of molecules