$$CH4(g)+2O2(g)$$⟶$$CO2(g)+2H2O(g)According$$ to the above chemical reaction, following information have been given.(i) One mole of $$CH4$$ (g$$ $$) reacts with two moles of $$O2(g)$$ to give one mole of $$CO2(g)$$ and two moles of $$H2O$$ (g)(ii) One molecule of $$CH4$$ (g) reacts with $$2$$ molecules of $$O2(g)$$ to give one molecule of $$CO2(g)$$ and $$2$$ molecules of $$H2O(g)(iii)$$ $$22.4$$ L of $$CH4(g$$ $$)$$ reacts with $$45.4$$ L of $$O2$$ to give $$22.7$$ L of $$CO2(g)$$ and $$45.4$$ L of $$H2O(g)(iv)$$ $$16$$ g of $$CH4(g$$ $$)$$ reacts with $$2x$$ $$32$$ g of $$O2$$ (g$$ $$) to give $$44$$ g of $$CO2(g)$$ and $$2x$$ $$18$$ g of $$H2O(g)From$$ these information the true interconversion should be

Question

$$CH4(g)+2O2(g)$$⟶$$CO2(g)+2H2O(g)According$$ to the above chemical reaction, following information have been given.(i) One mole of $$CH4$$ (g$$ $$) reacts with two moles of $$O2(g)$$ to give one mole of $$CO2(g)$$ and two moles of $$H2O$$ (g)(ii) One molecule of $$CH4$$ (g) reacts with $$2$$ molecules of $$O2(g)$$ to give one molecule of $$CO2(g)$$ and $$2$$ molecules of $$H2O(g)(iii)$$ $$22.4$$ L of $$CH4(g$$ $$)$$ reacts with $$45.4$$ L of $$O2$$ to give $$22.7$$ L of $$CO2(g)$$ and $$45.4$$ L of $$H2O(g)(iv)$$ $$16$$ g of $$CH4(g$$ $$)$$ reacts with $$2x$$ $$32$$ g of  $$O2$$ (g$$ $$) to give $$44$$ g of $$CO2(g)$$ and $$2x$$ $$18$$ g of $$H2O(g)From$$ these information the true interconversion should be

Infinity Learn · Accepted Answer

From the given relationships, the data can be interconverted asmass ⇌  moles ⇌  number of molecules

Detailed Solution

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