CH4(g)+2O2(g)⟶CO2(g)+2H2O(g)How many moles of methane are required to produce 22 g CO2(g) after combustion?

According to the chemical equationCH4(g)+2O2(g)⟶CO2(g)+2H2O(g)44 gCO2(g) is obtained from 16 gCH4(g)∵1 mole CO2(g) is obtained from 1 mole of CH4(g) Mole of CO2(g)=22 gCO2(g)44 gCO2(g)                         = 0.5 mole CO2(g) Hence, 0.5 mole CO2(g) would be obtained from 0.5 mole CH4(g) or 0.5 mole of CH4(g) would be required to  produce 22 gCO2(g).