Q.
In a chemical equilibrium, the rate constant of the backward reaction is 7.5 × 10-4 and the equilibrium constant is 1.5. So the rate constant of the forward reaction is
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a
5 × 10-4
b
2 × 10-3
c
1.125 × 10-3
d
9.0 × 10-4
answer is C.
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Detailed Solution
KC=KfKbKf=Kc × Kb=1.5×7.5×10-4=1.125×10-3