Q.

In a chemical equilibrium, the rate constant of the backward reaction is 7.5 × 10-4 and the equilibrium constant is 1.5. So the rate constant of the forward reaction is

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a

5 × 10-4

b

2 × 10-3

c

1.125 × 10-3

d

9.0 × 10-4

answer is C.

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Detailed Solution

KC=KfKbKf=Kc × Kb=1.5×7.5×10-4=1.125×10-3
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