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In the chemical reaction X⇌Y , the standard Gibb’s energy depends on temperature T(in kelvin) as ΔGreaction in KJ.mole-1=120-38TThe major component in the equilibrium mixture at given temperature is
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a
X, if T=320K
b
X, if T=350K
c
Y, if T=300K
d
Y, if T=280K
answer is A.
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Detailed Solution
ΔGreaction =ΔG0+2.303RTlog(Q)At equilibrium ΔGreaction =0 , by comparing the given equation at equilibrium 120=38TT = 320 KIs temperature is less than 320 K reaction quotient (Q) will be greater than equilibrium constant. Which drive the equilibrium backward ΔGBachward =-vemake ‘X’ as major product
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