Choose the correct statement(s) among the following.

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

SnCl2.2H2O is a reducing agent

SnO2 reacts with KOH to form K2[Sn(OH)6].

A solution of PbCl2 in HCl contains Pb2+ and Cl− ions.

The reaction of Pb3O4 with hot dilute nitric acid to give PbO2 is a redox reaction.

answer is A.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

1) SnCl2⋅2H2O is a reducing agent since Sn2+ tends to convert into Sn4+.2) SnO2 (Amphoteric) +2KOH(aq.) (Base )+2H2O⟶K2Sn(OH)63) First group cations (Pb2+) form insoluble chloride with HCl that is PbCl2 however it is slightly soluble in water and therefore lead +2 ion is never completely precipitated on adding hydrochloric acid in test sample of Pb2+, rest of the Pb2+ ions are quantitatively precipitated with H2S in acidic medium. So that we can say that filtrate of first group contain solution of PbCl2 in HCl which contains Pb2+ and Cl– However in the presence of conc. HCl or excess HCl it can produce H2[PbCl4] So, we can conclude 1, 2 or 1,2,3 should be answers. 4) Pb3O42PbO.PlbO2 (mixture of oxides) +4HNO3⟶PbO2(↓)+2PbNO32+2H2O It is not a redox reaction

Watch 3-min video & get full concept clarity