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Choose the correct value of $\frac{d [{NH}_{3}]}{dt}$ for the reaction, $N_{2} + 3 H_{2} ⟶ 2 {NH}_{3}$

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−23dH2dt

23dH2dt

32dN2dt

−32dN2dt

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Correct option is A

−dN2dt=−dH23dt=+dNH32dt or dNH3dt=−23dH2dt

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Choose the correct value of dNH3dt for the reaction, N2+3H2⟶2NH3

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Choose the correct value of $\frac{d [{NH}_{3}]}{dt}$ for the reaction, $N_{2} + 3 H_{2} ⟶ 2 {NH}_{3}$