In Clarke’s process, the salts responsible for hardness get precipitated as
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a
MgCO3, CaOH2
b
MgOH2, CaOH2
c
MgOH2, CaCO3
d
MgCO3, CaCO3
answer is C.
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Detailed Solution
CaHCO32 and MgHCO32are responsible for temperorary hardness of water which are removed in Clarke's process;CaHCO32+ CaOH2 → CaCO3↓+H2O+CO2MgHCO32+ 2CaOH2 → CaCO3↓+MgOH2↓+H2O+CO2Ksp of MgOH2 < Ksp of MgCO3 ∴ MgOH2 is precipitated but not MgCO3