In Clarke’s process, the salts responsible for hardness get precipitated as
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
MgCO3, CaOH2
b
MgOH2, CaOH2
c
MgOH2, CaCO3
d
MgCO3, CaCO3
answer is C.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
CaHCO32 and MgHCO32are responsible for temperorary hardness of water which are removed in Clarke's process;CaHCO32+ CaOH2 → CaCO3↓+H2O+CO2MgHCO32+ 2CaOH2 → CaCO3↓+MgOH2↓+H2O+CO2Ksp of MgOH2 < Ksp of MgCO3 ∴ MgOH2 is precipitated but not MgCO3