Q.

In Clarke’s process, the salts responsible for hardness get precipitated as

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a

MgCO3,  CaOH2

b

MgOH2,  CaOH2

c

MgOH2,  CaCO3

d

MgCO3,  CaCO3

answer is C.

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Detailed Solution

CaHCO32 and  MgHCO32are responsible for temperorary hardness of water which are removed in Clarke's process;CaHCO32+ CaOH2 → CaCO3↓+H2O+CO2MgHCO32+ 2CaOH2 → CaCO3↓+MgOH2↓+H2O+CO2Ksp of  MgOH2 < Ksp of MgCO3    ∴ MgOH2 is  precipitated  but  not  MgCO3
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