First slide

Hardness of water

Question

In Clark's method, the substance used for the removal of temporary hardness of water is

Easy

A

NaOH
B

CaCO₃
C

Ca(OH)₂
D

Ca(HCO₃)₂

Solution

In clark's method, the substance used for the removal of temparary hardness of water is Ca(OH)₂ (lime water)
$\large \mathop {Ca{{[HC{O_3}]}_2}}\limits_{so\operatorname{lub} le} + Ca(OH) \to \mathop {2CaC{O_3} \downarrow }\limits_{ppt} + 2{H_2}O\$
$\large \mathop {Mg{{(HC{O_3})}_2}}\limits_{so\operatorname{lub} le} + Ca(OH) \to \mathop {MgC{O_3} \downarrow }\limits_{ppt} + \mathop {CaC{O_3} \downarrow }\limits_{ppt} + 2{H_2}O\$
In this process the soluble bicarbonates converting to insoluble carbonates on heating with Ca(OH)₂.

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