Q.

In a closed container and at constant temperature 0.3 mole of SO2 & 0.2 mole of O2  gas at 750 torr are kept with a catalyst. If at equilibrium 0.2 mole of SO3  is formed the partial pressure of SO2  is........ torr

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a

375

b

187

c

360

d

150

answer is D.

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Detailed Solution

2SO2  +  O2⇌  2SO3               0.3         0.2             0                     2x           x              2x  _    (0.3−2x)     (0.2−x)    2x          0.1                   0.1          0.2 Given 2x = 0.2 mole               x= 0.1 mole 0.5 mole               750 torr0.4 mole                  ?                          =600 torr ∴ PSO2=0.10.4×600=150 torr
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