Q.
In a closed container and at constant temperature 0.3 mole of SO2 & 0.2 mole of O2 gas at 750 torr are kept with a catalyst. If at equilibrium 0.2 mole of SO3 is formed the partial pressure of SO2 is........ torr
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a
375
b
187
c
360
d
150
answer is D.
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Detailed Solution
2SO2 + O2⇌ 2SO3 0.3 0.2 0 2x x 2x _ (0.3−2x) (0.2−x) 2x 0.1 0.1 0.2 Given 2x = 0.2 mole x= 0.1 mole 0.5 mole 750 torr0.4 mole ? =600 torr ∴ PSO2=0.10.4×600=150 torr
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