In a closed container for the reaction H2(g)+I2(g)⇌2HI(g) the equilibrium concentrations H2=0.5M,I2=0.5M and [HI]=1.25M. If 0.5 moles of HI was added to 1 L of equilibrium mixture, then H2 at new equilibrium mixture is

Equilibrium constant KC=[HI]2H2I2 =[1.25]2[0.5][0.5] =6.25                                H22,+I2(g)⇌2HI  at old equilibrium     0.5     0.5     1.25 at new equilibrium +x20.5+x2+x20.5+x2  -x1.75-x (1.75-x)20.5+x20.5+x2=6.25 1.75-x0.5+x2=2.5 1.75-x=1.25+1.25 x 2.25 x=0.5 x=0.222 Equilibrium concentration of H2=0.61M