A closed container was divided in to two equal half with a thin metal plate. In one half equilibrium CuSO4·3H2O(S)+2H2O(g)⇌CuSO4.5H2O(S) has been established with equilibrium pressure 0.1 atm and in the other half H2O(s)⇌H2O(g)equilibrium established at a pressure of 0.2 atm. If temperature is same in both halfs what happens if the metal plate was removed

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Amount of CuSO4·5H2O solid will decrease

Amount of ice will increase

Amount of CuSO4·3H2O solid will decrease

Equilibrium constant of H2O(s)⇌H2O(g) system increases.

answer is C.

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Detailed Solution

When the metal plate was removed the pressure in the container become 0.15 atm. So CuSO4·3H2O(S)+2H2O(g)⇌CuSO4·5H2O(S) equilibrium proceed in forward direction and H2O(S)⇌H2O(g)proceed in forward direction.

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