A closed vessel of volume V litre has the equilibrium moles of N2,H2 and NH3 as 1,5 and 0.2 moles respectively. If equilibrium constant for N2(g)+3H2(g)⇌2NH3(g is 2×10-3 mol-2lit2at constant temperature, the value of 'V' is

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answer is 2.5.

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Detailed Solution

Equilibrium constant Kc=NH32N2H232×10-3=0.2V21V5V3 V=2.5 litre

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