A closed vessel of volume V litre has the equilibrium moles of N2,H2 and NH3 as 1,5 and 0.2 moles respectively. If equilibrium constant for N2(g)+3H2(g)⇌2NH3(g is 2×10-3 mol-2lit2at constant temperature, the value of 'V' is

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

answer is 2.5.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Equilibrium constant Kc=NH32N2H232×10-3=0.2V21V5V3 V=2.5 litre

Watch 3-min video & get full concept clarity